document.write( "Question 174494: Quadrilateral ABCD has vertices A(-1,0), B(3,3), C(6,-1), and D(2,-4). Prove that quadrilateral ABCD is a square. \n" ); document.write( "

Algebra.Com's Answer #129496 by checkley77(12844) $\"\"$ $\"About$

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A(-1,0), B(3,3), C(6,-1), D(2,-4).
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\n" ); document.write( "AB=(3-0)/(3+1)=3/4
\n" ); document.write( "DC=(-4+1)/(2-6)=3/4 THUS THESE 2 LINES ARE PARALLEL.
\n" ); document.write( "slopes:
\n" ); document.write( "BC=(-1-3)/6-3)=-4/3=-4/3
\n" ); document.write( "AD=(-4-0)/(2+1)=-4/3 THESE 2 LINES ARE PARALLEL & PERPENDICULAR TO THE AB & DC LINES.
\n" ); document.write( "THUS THIS IS A SQUARE FIGURE. \r
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