document.write( "Question 174475: 6. find the exact value of trigonomic fucntion sec2x sin=3/5
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Algebra.Com's Answer #129488 by rapaljer(4671)\"\" \"About 
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Presumably you mean that sin x = 3/5 and cos x = 4/5.\r
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\n" ); document.write( "\n" ); document.write( "Then, \"cos+2x+=+2+%28cos+x%29+%5E2+-+1+\"
\n" ); document.write( "\"cos+2x+=+2%2A%284%2F5%29%5E2+-1+\"
\n" ); document.write( "\"cos+2x+=+2%2A16%2F25+-1\"
\n" ); document.write( "\"cos+2x+=+32%2F25+-+1\"
\n" ); document.write( "\"cos+2x+=+32%2F25+-+25%2F25+=+7%2F25\"\r
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\n" ); document.write( "\n" ); document.write( "Now, \"sec+2x+=+1%2F%28cos+2x%29+=+25%2F7+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2
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