document.write( "Question 174481This question is from textbook algebra 1
\n" );
document.write( ": you can find the perimeter of rectangle if you subtract the width from the length, add 7 inches, and multiply the result by 4.\r
\n" );
document.write( "\n" );
document.write( "a.If the rectangle's length is l and its width is w, what is the perimeter? \n" );
document.write( "
Algebra.Com's Answer #129477 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! you can find the perimeter of rectangle if you subtract the width from the length, add 7 inches, and multiply the result by 4. \n" ); document.write( ": \n" ); document.write( "P = 4(L - W + 7) \n" ); document.write( ": \n" ); document.write( "a.If the rectangle's length is l and its width is w, what is the perimeter? \n" ); document.write( ": \n" ); document.write( "P = 4(1 - w + 7) \n" ); document.write( ": \n" ); document.write( "P = 4(8 - w) \n" ); document.write( ": \n" ); document.write( "P = 32 - 4w \n" ); document.write( ": \n" ); document.write( "Find P; we know 2L + 2w = 32 - 4w, substitute 1 for L \n" ); document.write( "2 + 2w = 32 - 4w \n" ); document.write( ": \n" ); document.write( "2w + 4w = 32 - 2 \n" ); document.write( ": \n" ); document.write( "6w = 30 \n" ); document.write( "w = \n" ); document.write( "w = 5 \n" ); document.write( ": \n" ); document.write( "P = 2(1) + 2(5) \n" ); document.write( "P = 12 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equation \n" ); document.write( "P = 4(1 - 5 + 7) \n" ); document.write( "P = 4(3) \n" ); document.write( "p = 12 \n" ); document.write( " |