document.write( "Question 174460: find the value of x.\r
\n" );
document.write( "\n" );
document.write( "3x + 15\r
\n" );
document.write( "\n" );
document.write( "4x + 12 \n" );
document.write( "
Algebra.Com's Answer #129463 by cloudstrifeo0o(5)![]() ![]() You can put this solution on YOUR website! This is how I was taught: \r \n" ); document.write( "\n" ); document.write( "3x + 15 | 4x + 12\r \n" ); document.write( "\n" ); document.write( "Set the equation to 0.\r \n" ); document.write( "\n" ); document.write( "3x + 15 = 0 | 4x + 12 = 0 \n" ); document.write( " -15 -15 | -12 -12 \n" ); document.write( "Subtract by 15. | Subtract by 12\r \n" ); document.write( "\n" ); document.write( "3x = -15 | 4x = -12 \n" ); document.write( "/3 /3 | /4 /4 \n" ); document.write( "Divide by 3 | Divide by 4\r \n" ); document.write( "\n" ); document.write( "x=-5 | x=-3\r \n" ); document.write( "\n" ); document.write( "I could be wrong, but I'm pretty sure it's right. \n" ); document.write( " |