document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174466>Question 174466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boy is three years younger than his sister. if his age three years ago was two thirds her age at that time. what are their present ages ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129460 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=sister's present age; x-3 is sister's age three years ago<BR>\n" );
document.write( "Then x-3=boy's present; x-6=boy's age three years ago\r<BR>\n" );
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document.write( "Now we are told the following<BR>\n" );
document.write( "x-6=(2/3)(x-3)  multiply each term by 3<BR>\n" );
document.write( "3x-18=2x-6  add 18 to and subtract 2x from each side<BR>\n" );
document.write( "3x-2x=12<BR>\n" );
document.write( "x=12---------------------sister's present<BR>\n" );
document.write( "x-3=12-3=9-----------------boy's present age\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "9-3=(2/3)(12-3)<BR>\n" );
document.write( "6=(2/3)(9)=6<BR>\n" );
document.write( "6=6\r<BR>\n" );
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document.write( "Does this help???----ptaylor </SPAN>\n" );
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