document.write( "Question 174444: 60 find all the solution in the interval 0,2pi
\n" ); document.write( " sin(x+pi/6)-sin(x-pi/6)=1/2
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Algebra.Com's Answer #129436 by jim_thompson5910(35256)\"\" \"About 
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\"sin%28x%2Bpi%2F6%29-sin%28x-pi%2F6%29=1%2F2\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"%28sin%28x%29cos%28pi%2F6%29%2Bcos%28x%29sin%28pi%2F6%29%29-sin%28x-pi%2F6%29=1%2F2\" Expand \"sin%28x%2Bpi%2F6%29\"\r
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\n" ); document.write( "\n" ); document.write( " Expand \"sin%28x-pi%2F6%29\"\r
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\n" ); document.write( "\n" ); document.write( " Distribute\r
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\n" ); document.write( "\n" ); document.write( " Evaluate \"cos%28pi%2F6%29\" to get \"sqrt%283%29%2F2\". Evaluate \"sin%28pi%2F6%29\" to get \"1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( " Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28x%29=1%2F2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28x%29=arccos%281%2F2%29\" Take the arccosine of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=pi%2F3\" or \"x=-pi%2F3\" Take the arccosine of 1/2 to get \"pi%2F3\" or \"-pi%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Since the value \"x=-pi%2F3\" is NOT in the range [0,2pi), this means that \"-pi%2F3\" is NOT a solution\r
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\n" ); document.write( "\n" ); document.write( "So the first solution is \"x=pi%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Now add \"2pi\" to \"pi%2F3\" to get \"2pi%2Bpi%2F3=6pi%2F3%2Bpi%2F3=%287pi%29%2F3\". Take note how this value is outside the interval [0,2pi). So this value is NOT a solution\r
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\n" ); document.write( "\n" ); document.write( "Now add \"2pi\" to \"-pi%2F3\" to get \"2pi-pi%2F3=6pi%2F3-pi%2F3=%285pi%29%2F3\". Since this value is inside the interval [0,2pi), this means that \"%285pi%29%2F3\" is a solution\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=pi%2F3\" or \"%285pi%29%2F3\"
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