document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174424>Question 174424</A>: <I><SPAN STYLE=\"word-break: break-all;\">  takes the length=12 and width=4 of a rectangular yard and the length and width of a rectangular house situated in the yard. Your  should compute the time required to cut the grass at the rate of two square feet a second.\r<BR>\n" );
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document.write( "solve this question .its urgent\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129411 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  take the length=12 and width=4 of a rectangular yard and the length and width of a rectangular house situated in the yard. Your should compute the time required to cut the grass at the rate of two square feet a second.<BR>\n" );
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document.write( "Find the area of the yard: 12 * 4 = 48 sq/ft<BR>\n" );
document.write( "Let x = area of the house in sq/ft<BR>\n" );
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document.write( "Time (in sec) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%2848-x%29%29%2F2 ALIGN=MIDDLE  ALT=\"%28%2848-x%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >  </SPAN>\n" );
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