document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174422>Question 174422</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The present age of a father is three times that of his son but after 22 ears it will be only twice that of his son. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129408 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     The present age of a father is three times that of his son but after 22 ears it will be only twice that of his son. Find their present ages.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = son's age<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3x = father's age<BR>\n" );
document.write( ".<BR>\n" );
document.write( "3x+22 = 2(x+22)<BR>\n" );
document.write( "3x+22 = 2x+44<BR>\n" );
document.write( "x+22 = 44<BR>\n" );
document.write( "x = 22 years (son's age)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "father's age:<BR>\n" );
document.write( "3x = 3(22) = 66 years (father's age)<BR>\n" );
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