document.write( "Question 174167: 5/3x-1 - x-7/9x^-1=-2/3x+1
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Algebra.Com's Answer #129354 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Assume that the problem is actually: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "(9x^2-1) is difference of squares, factor this: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by (3x+1)(3x-1) \n" ); document.write( "(3x+1)(3x-1)* \n" ); document.write( ": \n" ); document.write( "Cancel out the denominators: \n" ); document.write( "5(3x+1) - (x-7) = -2(3x-1) \n" ); document.write( ": \n" ); document.write( "15x + 5 - x + 7 = -6x + 2 \n" ); document.write( ": \n" ); document.write( "14x + 12 = -6x + 2 \n" ); document.write( ": \n" ); document.write( "14x + 6x = 2 - 12 \n" ); document.write( ": \n" ); document.write( "20x = -10 \n" ); document.write( "x = \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "You can check the solution in the original equation using x=-.5 \n" ); document.write( " |