document.write( "Question 24338: Tad has 6 more quarters than dimes. If he has $3.25 total, how many coins of each type does he have? \n" ); document.write( "
Algebra.Com's Answer #12926 by Paul(988)\"\" \"About 
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quartes = 6+x
\n" ); document.write( "dimes = x
\n" ); document.write( "Total value = 325
\n" ); document.write( "Dime value = 10
\n" ); document.write( "Quarter value = 25\r
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\n" ); document.write( "\n" ); document.write( "25(x+6)+10x=325
\n" ); document.write( "25x+150+10x=325 (simplify)
\n" ); document.write( "35x=175
\n" ); document.write( "x=5\r
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\n" ); document.write( "\n" ); document.write( "6+5 = 11\r
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\n" ); document.write( "\n" ); document.write( "Hence there were 5 dimes and 11 quarters.
\n" ); document.write( "Paul.
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