document.write( "Question 24338: Tad has 6 more quarters than dimes. If he has $3.25 total, how many coins of each type does he have? \n" ); document.write( "
Algebra.Com's Answer #12926 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! quartes = 6+x \n" ); document.write( "dimes = x \n" ); document.write( "Total value = 325 \n" ); document.write( "Dime value = 10 \n" ); document.write( "Quarter value = 25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25(x+6)+10x=325 \n" ); document.write( "25x+150+10x=325 (simplify) \n" ); document.write( "35x=175 \n" ); document.write( "x=5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6+5 = 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence there were 5 dimes and 11 quarters. \n" ); document.write( "Paul. \n" ); document.write( " |