document.write( "Question 174247: I don't know how to type this, so I'll try to explain it.
\n" ); document.write( "Square root symbol, with 6 outside (but inside the little section), and inside the square root is another square root symbol. Inside this second square root symbol is a 2. Now subtract from that: square root with 12 inside the little part, and inside the square root is 2 with exponent of 13.\r
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Algebra.Com's Answer #129199 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Is the expression \"root%286%2Csqrt%282%29%29-root%2812%2C2%5E13%29\" ???\r
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\n" ); document.write( "\n" ); document.write( "\"root%286%2Csqrt%282%29%29-root%2812%2C2%5E13%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"root%286%2Csqrt%282%29%29-root%2812%2C2%5E%2812%2B1%29%29\" Break up \"2%5E%2813%29\" to \"2%5E%2812%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"root%286%2Csqrt%282%29%29-root%2812%2C2%5E%2812%29%2A2%5E%281%29%29\" Break up the exponent (see note below)\r
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\n" ); document.write( "\n" ); document.write( "\"root%286%2Csqrt%282%29%29-root%2812%2C2%5E%2812%29%29%2Aroot%2812%2C2%5E%281%29%29%29\" Break up the square root (see note below).\r
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\n" ); document.write( "\n" ); document.write( "\"root%286%2Csqrt%282%29%29-2%2Aroot%2812%2C2%29\" Take the 12th root of \"2%5E12\" to get 2 (see note below).\r
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\n" ); document.write( "\n" ); document.write( "\"root%286%2C2%5E%281%2F2%29%29-2%2Aroot%2812%2C2%29\" Convert from radical notation to exponential notation. So \"sqrt%282%29=2%5E%281%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282%5E%281%2F2%29%29%5E%281%2F6%29-2%2Aroot%2812%2C2%29\" Convert from radical notation to exponential notation. So \"root%286%2C2%5E%281%2F2%29%29=%282%5E%281%2F2%29%29%5E%281%2F6%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282%5E%281%2F2%29%29%5E%281%2F6%29-2%2A2%5E%281%2F12%29\" Convert from radical notation to exponential notation. So \"root%2812%2C2%29=2%5E%281%2F12%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E%281%2F12%29-2%2A2%5E%281%2F12%29\" Multiply the exponents \"1%2F2\" and \"1%2F6\" to get \"1%2F12\"\r
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\n" ); document.write( "\n" ); document.write( "Take note that the GCF is \"2%5E%281%2F12%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E%281%2F12%29%281-2%29\" Factor out the GCF \"2%5E%281%2F12%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E%281%2F12%29%28-1%29\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "\"root%2812%2C2%29%28-1%29\" Convert from exponential notation to radical notation. So \"2%5E%281%2F12%29=root%2812%2C2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-root%2812%2C2%29\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"root%286%2Csqrt%282%29%29-root%2812%2C2%5E13%29=-root%2812%2C2%29\" (Note: the right side reads the negative 12th root of 2)\r
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\n" ); document.write( "\n" ); document.write( "Notes:\r
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\n" ); document.write( "\n" ); document.write( "I used the following identities to simplify the expression:\r
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\n" ); document.write( "\n" ); document.write( "1) \"x%5E%28y%2Bz%29=x%5Ey%2Ax%5Ez\"\r
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\n" ); document.write( "\n" ); document.write( "2) \"sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29\"\r
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\n" ); document.write( "\n" ); document.write( "3) \"root%28n%2Cx%5En%29=x\"
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