document.write( "Question 174242: I really need help with this, I've been given the rules, but I don't under stand how to apply it. Thanks so much for your help!\r
\n" ); document.write( "\n" ); document.write( "1. Convert the following equations into logarithmic form:\r
\n" ); document.write( "\n" ); document.write( " a. 6 = 2x (x is the exponent)\r
\n" ); document.write( "\n" ); document.write( " b. 9 = 6y (y is the exponent)\r
\n" ); document.write( "\n" ); document.write( " c. 7 = 3y (y is the exponent)\r
\n" ); document.write( "\n" ); document.write( " d. X = 5y (y is the exponent)
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Algebra.Com's Answer #129176 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The main thing to remember is this:
\n" ); document.write( "***** Logs are exponents! *****
\n" ); document.write( "Say or write it 10 times and you'll be fine
\n" ); document.write( "Ok, the 1st problem is
\n" ); document.write( "a) \"6+=+2%5Ex\"
\n" ); document.write( "What's the log here? It's the exponent \"x\"
\n" ); document.write( "OK, now I can write
\n" ); document.write( "log = x
\n" ); document.write( "What is the rest of it? Logs need a base, the same as exponents, so
\n" ); document.write( "log (base 2) = x
\n" ); document.write( "The last bit of info is what the result is when \"2\" is raised
\n" ); document.write( "to the log (or exponent)\"x\"
\n" ); document.write( "You write it like this:
\n" ); document.write( "\"log%282%2C6%29=+x\" this says
\n" ); document.write( "\"x\" is a log
\n" ); document.write( "\"2\" is the base
\n" ); document.write( "\"6\" is the result
\n" ); document.write( "---------------------
\n" ); document.write( "b) \"9+=+6%5Ey\"
\n" ); document.write( "\"log%286%2C9%29+=+y\"
\n" ); document.write( "\"y\" is a log
\n" ); document.write( "\"6\" is the base
\n" ); document.write( "\"9\" is the result
\n" ); document.write( "---------------------
\n" ); document.write( "You should be able to do the rest\r
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