document.write( "Question 174242: I really need help with this, I've been given the rules, but I don't under stand how to apply it. Thanks so much for your help!\r
\n" ); document.write( "\n" ); document.write( "1. Convert the following equations into logarithmic form:\r
\n" ); document.write( "\n" ); document.write( " a. 6 = 2x (x is the exponent)\r
\n" ); document.write( "\n" ); document.write( " b. 9 = 6y (y is the exponent)\r
\n" ); document.write( "\n" ); document.write( " c. 7 = 3y (y is the exponent)\r
\n" ); document.write( "\n" ); document.write( " d. X = 5y (y is the exponent)
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Algebra.Com's Answer #129175 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
\"x=b%5Ey\" means \"log%28b%2Cx%29=y\"
\n" ); document.write( " 1. Convert the following equations into logarithmic form:
\n" ); document.write( "a. 6 = 2x (x is the exponent)
\n" ); document.write( "b. 9 = 6y (y is the exponent)
\n" ); document.write( "c. 7 = 3y (y is the exponent)
\n" ); document.write( "d. X = 5y (y is the exponent)
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "a. \"log%282%2C6%29=x\"
\n" ); document.write( "b. \"log%286%2C9%29=y\"
\n" ); document.write( "c \"log%283%2C7%29=y\"
\n" ); document.write( "d. \"log%285%2Cx%29=y\"
\n" ); document.write( "
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