document.write( "Question 174206: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mph and train B is traveling at 80 mph. Train A passes a station at 4:10am. If train B passes the same station at 4:22am. at what time will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #129145 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks. \n" ); document.write( "----------------------------- \n" ); document.write( "Train A is traveling at 60 mph and train B is traveling at 80 mph. \n" ); document.write( "----------------------------- \n" ); document.write( "Train A passes a station at 4:10am. If train B passes the same station at 4:22am. \n" ); document.write( "------------- \n" ); document.write( "At what time will train B catch up to train A? \n" ); document.write( "-------------------------------------- \n" ); document.write( "Train A DATA: \n" ); document.write( "rate = 60 mph ; distance = x miles ; time = x/60 hours \n" ); document.write( "-------------- \n" ); document.write( "Train B DATA: \n" ); document.write( "rate = 80mph ; distance = x miles ; time = x/80 hours \n" ); document.write( "-------------- \n" ); document.write( "EQUATION: \n" ); document.write( "A time - B time = (12/60) hour \n" ); document.write( "x/60 - x/80 = 1/5 hr \n" ); document.write( "x/12 - x/16 = 1 \n" ); document.write( "(16x - 12x) = 12*16 \n" ); document.write( "4x = 12*16 \n" ); document.write( "x = 3*16 = 48 miles \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |