document.write( "Question 174209: divide \r
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document.write( "Solve \r
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document.write( "write as a single log \r
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document.write( "A radioactive isotope has a halflife of 600 years. If 50g is on hand now, how much will be available in 1000 years?\r
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Algebra.Com's Answer #129144 by stanbon(75887) ![]() You can put this solution on YOUR website! divide \n" ); document.write( "Use synthetic division: \n" ); document.write( "3)....1....0....1....0....2....7 \n" ); document.write( ".......1....3....10...30...92..|..283\r \n" ); document.write( "\n" ); document.write( "Quotient: x^4 + 3x^3 + 10x^2 + 30x + 92 \n" ); document.write( "Remainder: 283 \n" ); document.write( "==========================================\r \n" ); document.write( "\n" ); document.write( "Solve \n" ); document.write( "xlog(4) = log(12) \n" ); document.write( "x = log(12)/log(4) = 1.7925 \n" ); document.write( "===========================================\r \n" ); document.write( "\n" ); document.write( "write as a single log \n" ); document.write( "log(x^3) - log(y^(1/3)) + log(z^4)\r \n" ); document.write( "\n" ); document.write( "= log[x^3*z^4/y^(1/3)]\r \n" ); document.write( "\n" ); document.write( "============================================\r \n" ); document.write( "\n" ); document.write( "A radioactive isotope has a halflife of 600 years. If 50g is on hand now, how much will be available in 1000 years? \n" ); document.write( "--- \n" ); document.write( "A(t) = Ao (1/2)^(t/600) \n" ); document.write( "A(1000) = 50*(1/2)^(1000/600) \n" ); document.write( "A(1000) = 50*0.31498 \n" ); document.write( "A(1000) = 15.749 grams \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |