document.write( "Question 174207: Soybean meal is 18% protein, cornmeal is 9% protein. How many pounds of each should be mixed together in order to get 360Lb. mixture that is 11% protein.\r
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document.write( "How many Lbs. of the cornmeal should be in the mixture?\r
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document.write( "How many Lbs. o the soybeans should be in the mixture?\r
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document.write( "( I don't understand word problems that well can someone help me solve this?) \n" );
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Algebra.Com's Answer #129140 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! let the number of pounds of soybean and cornmeal be s and c respectively \n" ); document.write( "we know there are 360 pounds altogether \n" ); document.write( ": \n" ); document.write( "s+c=360................eq 1 \n" ); document.write( ".18s+.09c=.11(360).....eq 2 \n" ); document.write( ": \n" ); document.write( "lets rewrite eq 1 to s=360-c and take that value and plug it into eq 2 \n" ); document.write( ": \n" ); document.write( ".18(360-c)+.09c=39.6 \n" ); document.write( ": \n" ); document.write( "64.8-.18c+.09c=39.6 \n" ); document.write( ": \n" ); document.write( "-.09c=-25.5 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This makes alot of sense because the cornmeal is 9% protein which is much closer to the final mixture of 11% protein that the soybean which is 18%. So it definitely fits that we use alot more of the cormeal mix to reach our 11% protein goal \n" ); document.write( " |