document.write( "Question 174181This question is from textbook algebra 1
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\n" ); document.write( "a. |x-5|=3
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Algebra.Com's Answer #129134 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"abs%28x-5%29=3\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29=a\", then \"x=-a\" or \"x=a\")\r
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\n" ); document.write( "\n" ); document.write( "\"x-5=-3\" or \"x-5=3\" Set the expression \"x-5\" equal to the original value 3 and it's opposite -3\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the first equation \"x-5=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3%2B5\"Add 5 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the second equation \"x-5=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2B5\"Add 5 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=8\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "So the solutions to \"abs%28x-5%29=3\" are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" and \"x=8\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=abs%28x-5%29\" and \"y=3\" (just set each side equal to y and graph), we get\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=abs%28x-5%29\" (red) and \"y=3\"(green)\r
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\n" ); document.write( "\n" ); document.write( "and we can see the two graphs intersect at \"x=2\" and \"x=8\". So this verifies our answer.\r
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