document.write( "Question 174186This question is from textbook algebra 1
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Algebra.Com's Answer #129131 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"abs%288-3x%29=2\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29=a\", then \"x=-a\" or \"x=a\")\r
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\n" ); document.write( "\n" ); document.write( "\"8-3x=-2\" or \"8-3x=2\" Set the expression \"8-3x\" equal to the original value 2 and it's opposite -2\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the first equation \"8-3x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=-2-8\"Subtract 8 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=-10\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-10%29%2F%28-3%29\" Divide both sides by -3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=10%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the second equation \"8-3x=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=2-8\"Subtract 8 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=-6\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-6%29%2F%28-3%29\" Divide both sides by -3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=10%2F3\" or \"x=2\"\r
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