document.write( "Question 174187This question is from textbook algebra 1
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Algebra.Com's Answer #129127 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You can simply count the spaces between the two points vertically to get 6 units, but here's the formal method to find the distance:\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%285-5%29%5E2%2B%283--3%29%5E2%29\" Plug in \"x%5B1%5D=5\", \"x%5B2%5D=5\", \"y%5B1%5D=3\", and \"y%5B2%5D=-3\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%280%29%5E2%2B%283--3%29%5E2%29\" Subtract \"5\" from \"5\" to get \"0\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%280%29%5E2%2B%286%29%5E2%29\" Subtract \"-3\" from \"3\" to get \"6\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%280%2B%286%29%5E2%29\" Square \"0\" to get \"0\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%280%2B36%29\" Square \"6\" to get \"36\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2836%29\" Add \"0\" to \"36\" to get \"36\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=6\" Take the square root of \"36\" to get \"6\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=6\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points is 6 units. \r
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