document.write( "Question 174180: if 5a=3a+10 evaluate -5a+3. \n" ); document.write( "
Algebra.Com's Answer #129116 by jim_thompson5910(35256)\"\" \"About 
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\"5a=3a%2B10\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"5a-3a=10\" Subtract \"3a\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2a=10\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"a=%2810%29%2F%282%29\" Divide both sides by \"2\" to isolate \"a\".\r
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\n" ); document.write( "\n" ); document.write( "\"a=5\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"-5a%2B3\" Move onto the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"-5%285%29%2B3\" Plug in \"a=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"-25%2B3\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"-22\" Add\r
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\n" ); document.write( "\n" ); document.write( "So \"-5a%2B3=-22\" when \"5a=3a%2B10\"
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