document.write( "Question 174179: What is the equation of the line that passes through the given points and is perpendicular to the given line?\r
\n" ); document.write( "\n" ); document.write( "(3,3), 2y=3x-6
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Algebra.Com's Answer #129114 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"2y=3x-6\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%283x-6%29%2F%282%29\" Divide both sides by \"2\" to isolate y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%283%29%2F%282%29%29x%2B%28-6%29%2F%282%29\" Break up the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%283%2F2%29x-3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "We can see that the equation \"y=%283%2F2%29x-3\" has a slope \"m=3%2F2\" and a y-intercept \"b=-3\".\r
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\n" ); document.write( "\n" ); document.write( "Now to find the slope of the perpendicular line, simply flip the slope \"m=3%2F2\" to get \"m=2%2F3\". Now change the sign to get \"m=-2%2F3\". So the perpendicular slope is \"m=-2%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope \"m=3%2F2\" and the coordinates of the given point .\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" Start with the point slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%28-2%2F3%29%28x-3%29\" Plug in \"m=-2%2F3\", \"x%5B1%5D=3\", and \"y%5B1%5D=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%28-2%2F3%29x%2B%28-2%2F3%29%28-3%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%28-2%2F3%29x%2B2\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x%2B2%2B3\" Add 3 to both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x%2B5\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line perpendicular to \"-3x%2B2y=-6\" that goes through the point is \"y=%28-2%2F3%29x%2B5\".\r
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\n" ); document.write( "\n" ); document.write( "Here's a graph to visually verify our answer:\r
\n" ); document.write( "\n" ); document.write( "Graph of the original equation \"y=%283%2F2%29x-3\" (red) and the perpendicular line \"y=%28-2%2F3%29x%2B5\" (green) through the point .
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