document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174172>Question 174172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is twice as long as it is wide. If both its dimensions are increasd by 4m, its area is increased by 88m^2. Make a sketch and find the dimensions of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129110 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Can't sketch.<BR>\n" );
document.write( "AREA=LW<BR>\n" );
document.write( "L=2W<BR>\n" );
document.write( "(L+4)(W+4)-LW=88<BR>\n" );
document.write( "(2W+4)(W+4)-2W*W=88<BR>\n" );
document.write( "2W^2+12W-2W^2+16-88=0<BR>\n" );
document.write( "12W-72=0<BR>\n" );
document.write( "12W=72<BR>\n" );
document.write( "W=72/12<BR>\n" );
document.write( "W=6m. ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=2*6=12m. ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "(12+4)(6+4)-12*6=88<BR>\n" );
document.write( "16*10=88+72<BR>\n" );
document.write( "160=160<BR>\n" );
document.write( "ORIGINAL DIMENSIONS ARE L=12 W=6. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );