document.write( "Question 174169: A house had two rooms of equal area. One room is square and the other roon is a rectangle 4ft narrower and 5ft longer than the square one. Find the area of each room. \n" ); document.write( "
Algebra.Com's Answer #129100 by jim_thompson5910(35256)\"\" \"About 
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Let x=side length of square\r
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\n" ); document.write( "\n" ); document.write( "Since \"A house had two rooms of equal area. One room is square and the other room is a rectangle 4ft narrower and 5ft longer than the square one.\", this means that \"x%5E2=%28x%2B5%29%28x-4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=%28x%2B5%29%28x-4%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=x%5E2%2Bx-20\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2%2Bx-20-x%5E2\" Subtract \"x%5E2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0=x-20\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"20=x\" Add 20 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=20\" which means that the side length of the square is 20 ft. So the area of the square is \"20%5E2=400\" square feet.\r
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\n" ); document.write( "\n" ); document.write( "So the length of the rectangle is \"20%2B5=25\" ft and the width is \"20-4=16\" ft. So the area of the rectangle is \"25%2A16=400\" square feet.
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