document.write( "Question 167026: One number is 3 smaller than another number. The square of the larger number is 9 larger than ten times the smaller number. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #129048 by solver91311(24713)\"\" \"About 
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Let \"x\" be the larger number. That means that the smaller number is \"x-3\". The square of the larger number is \"x%5E2\". Ten times the smaller number is \"10%28x-3%29=10x-30\" and the square of the larger number is \"9\" larger than that, so:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=10x-30%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-10x%2B21=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%28x-7%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "Hence, \"x=3\" or \"x=7\"\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "If the larger number is 3, then the smaller number must be 0, 3 squared is 9 which is 9 larger than ten times zero. Checks.\r
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\n" ); document.write( "\n" ); document.write( "If the larger number is 7, then the smaller number must be 4, 7 squared is 49 which is 9 larger than 10 times 4 (40).
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