document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174031>Question 174031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is twice as long as it is wide. if both its dimensions are are increased by 4m, its area is increased by 88 m squared. find dimensions of original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129034 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W<BR>\n" );
document.write( "AREA=LW<BR>\n" );
document.write( "88=(L+4)(W+4)-LW<BR>\n" );
document.write( "88=(2W+4)(W+4)-2W*W<BR>\n" );
document.write( "88=2W^2+12W+16-2W^2<BR>\n" );
document.write( "88=12W=16<BR>\n" );
document.write( "12W=88-16<BR>\n" );
document.write( "12W=72<BR>\n" );
document.write( "W=72/12<BR>\n" );
document.write( "W=6M.<BR>\n" );
document.write( "L=2*6=12M.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "88=(12+4)(6+4)-12*6<BR>\n" );
document.write( "88=16*10-72<BR>\n" );
document.write( "88=160-72<BR>\n" );
document.write( "88=88\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );