document.write( "Question 174113: the four oldest people in Golden City lived a total of 384 years put together. The difference in ages for the youngest and the second oldest is 14. The second youngest is 3 years older than the youngest. The oldest is 20 years older than the average of the second and youngest. What are their ages? \n" ); document.write( "
Algebra.Com's Answer #129025 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let the ages, from youngest to oldest be \n" ); document.write( " \n" ); document.write( "Given: \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "(3) \n" ); document.write( "(4) \n" ); document.write( "------------------- \n" ); document.write( "(3) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(2) \n" ); document.write( "Subtract (3) from (2) \n" ); document.write( "(5) \n" ); document.write( " \n" ); document.write( "------------------- \n" ); document.write( "Substitute (4) and (5) in (1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(4) \n" ); document.write( " \n" ); document.write( "The ages from youngest to oldest are \n" ); document.write( "86.375, 89.375, 100.375, and 100.875 \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( "(2) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( "(3) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( "(4) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |