document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174049>Question 174049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of the area of a rectangle is 6x2+13x-5. If the demensions of nthe rectangle are represented by polynomials, find the demensions of the rectangle and then find its perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129023 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129023\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of rectangle=L*W=6x^2+13x-5\r<BR>\n" );
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document.write( "6x^2+13x-5=(3x-1)(2x+5)<BR>\n" );
document.write( "so, L*W=(3x-1)*(2x+5)--------------dimensions<BR>\n" );
document.write( "Perimeter=2L+2W=2(3x-1)+2(2x+5)=6x-2+4x+10=10x+8\r<BR>\n" );
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document.write( "Does this help???------ptaylor </SPAN>\n" );
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