document.write( "Question 174085: how do you solve b/b-1+2b/b^2-1 \n" ); document.write( "
Algebra.Com's Answer #129011 by nycsub_teacher(90)\"\" \"About 
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[b/(b - 1)] + [2b/(b^2 - 1)]\r
\n" ); document.write( "\n" ); document.write( "Look for LCD/\r
\n" ); document.write( "\n" ); document.write( "The LCD is b^2 - 1.\r
\n" ); document.write( "\n" ); document.write( "Divide the LCD by each denominator and then multiply the quotient by each numerator.\r
\n" ); document.write( "\n" ); document.write( "b^2 - 1 divided by b - 1 = b + 1\r
\n" ); document.write( "\n" ); document.write( "b^2 - 1 divided by itself = 1\r
\n" ); document.write( "\n" ); document.write( "We now have this:\r
\n" ); document.write( "\n" ); document.write( "[b(b + 1) + 2b(1)]/(b^2 - 1)\r
\n" ); document.write( "\n" ); document.write( "(b^2 + 3b)/(b^2 - 1)\r
\n" ); document.write( "\n" ); document.write( "The denominator is the difference of two perfect squares.\r
\n" ); document.write( "\n" ); document.write( "So, factor the denominator.\r
\n" ); document.write( "\n" ); document.write( "Final answer:\r
\n" ); document.write( "\n" ); document.write( "(b^2 + 3b)/(b - 1)(b + 1)\r
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