document.write( "Question 174082: How do you simplify by dividing n^3-27/n-3 \n" ); document.write( "

Algebra.Com's Answer #128983 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
This falls under the \"special factoring\" case -- \"difference of cubes\"
\n" ); document.write( "a^3 – b^3 = (a – b)(a^2 + ab + b^2)
\n" ); document.write( "For more info see:
\n" ); document.write( "http://www.purplemath.com/modules/specfact2.htm
\n" ); document.write( ".
\n" ); document.write( "Therefore for,
\n" ); document.write( "n^3-27/n-3
\n" ); document.write( "we can rewrite as:
\n" ); document.write( "(n^3 - 3^3)/n-3
\n" ); document.write( "the numberator can be then be factored:
\n" ); document.write( "(n-3)(n^2 + 3n + 9)/(n-3)
\n" ); document.write( "the (n-3) cancels leaving:
\n" ); document.write( "n^2 + 3n + 9 \n" ); document.write( "

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