document.write( "Question 174029: The lenght of a rectangle is twice the width. The perimeter is 84cm more than the width. Make a diagram and find the dimensions. \n" ); document.write( "

Algebra.Com's Answer #128982 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( " $\"L=2W\"$
\n" ); document.write( " $\"P=84cm\"$
\n" ); document.write( "then, $\"P=2L%2B2W\"$ , working eqn:
\n" ); document.write( " $\"84=2%282W%29%2B2W\"$
\n" ); document.write( " $\"84=4W%2B2W=6W\"$ --------> $\"cross%2884%2914%2Fcross%286%29=cross%286%29W%2Fcross%286%29\"$
\n" ); document.write( " $\"highlight%28W=14cm%29\"$
\n" ); document.write( " $\"L=2%2A14=highlight%2828cm=L%29\"$
\n" ); document.write( "Check via our working eqn:
\n" ); document.write( " $\"84cm=2%2A28%2B2%2A14\"$
\n" ); document.write( " $\"84=56%2B28\"$
\n" ); document.write( " $\"84cm=84cm\"$ good
\n" ); document.write( "See the diagram ratio 2:1, being Length is twice the Width:
\n" ); document.write( "
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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