document.write( "Question 174091: Please could you help me with this question that I have been et.
\n" ); document.write( "The question is to work out a formula for the area of a right angled triangle and then give the area when X=3
\n" ); document.write( "The sides of the triangle are 4x-1 and 4x+4\r
\n" ); document.write( "\n" ); document.write( "Please could you show the working out for this question.
\n" ); document.write( "Many thanks
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Algebra.Com's Answer #128977 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
The area of a triangle is given by \"A+=+bh%2F2\"\r
\n" ); document.write( "\n" ); document.write( "If you know the triangle is a right triangle, then you can just use the two 'shorter' sides. Let the shortest side be b and the middle length side be h.\r
\n" ); document.write( "\n" ); document.write( "You are given that the sides are in ratio x:4x-1:4x+4
\n" ); document.write( "So the longest side is 4x+4
\n" ); document.write( "That makes the short side, b = X = 3
\n" ); document.write( "The middle length side, h = 4x-1 = 12-1 = 11\r
\n" ); document.write( "\n" ); document.write( "\"A+=+bh%2F2\"
\n" ); document.write( "\"A+=+%283%2A11%29%2F2\"
\n" ); document.write( "\"A+=+33%2F2\" square units (whatever units x is in (the problem doesn't say
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