document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174054>Question 174054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> WRITE AN EQUATION OF A LINE THAT PASSES THROUGH THE GIVEN POINT IS PERPENDICULAR TO THE GIVEN LINE.\r<BR>\n" );
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document.write( "PROBLEM: (1,-1), Y=3X+2\r<BR>\n" );
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document.write( "PLEASE ANSWER AND GIVE ME THE STEPS TO SOLVE PROBLEMS SIMILAR TO THE ONE ABOVE.<BR>\n" );
document.write( "PLEASE EXPLAIN SO THAT I CAN MEMORIZE THE STEPS </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128959 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, recall that if two lines are perpendicular to each other, then their slopes are the negative reciprocal of each other. In other words, if you were to multiply the slopes of two perpendicular lines, the result would be -1.<BR>\n" );
document.write( "So first you need to find the slope of the line represented by the given equation: y = 3x+2.<BR>\n" );
document.write( "Since this equation is already in the \"slope-intercept\" form: y = mx+b, you can see that its slope, m = 3, so the negative reciprocal of 3 is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > and this will be the slope of the new line. You can then start the equation of the new line with:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%28-1%2F3%29x%2Bb ALIGN=MIDDLE  ALT=\"y+=+%28-1%2F3%29x%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" > Next, you need to find the value of b, the y-intercept.  You can do this by substituting the x- and y-coordinates of the given point (1, -1) into the equation above:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1+=+%28-1%2F3%29%281%29+%2B+b ALIGN=MIDDLE  ALT=\"-1+=+%28-1%2F3%29%281%29+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now you can solve this for the value of b. Add <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F3%29 ALIGN=MIDDLE  ALT=\"%281%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > to both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2B%281%2F3%29+=+b ALIGN=MIDDLE  ALT=\"-1%2B%281%2F3%29+=+b\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify the left side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+-2%2F3 ALIGN=MIDDLE  ALT=\"b+=+-2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now you can write the final equation for the new line.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y+=+%28-1%2F3%29x-2%2F3%29 ALIGN=MIDDLE  ALT=\"highlight%28y+=+%28-1%2F3%29x-2%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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