document.write( "Question 174002: how do you write the expression as a single logarithum:
\n" ); document.write( "1/2[log(base4)(x+1) + 2log(base4)(x-1)] +6log(base4)(x)
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Algebra.Com's Answer #128939 by gonzo(654)\"\" \"About 
You can put this solution on YOUR website!
your equation is:
\n" ); document.write( "1/2[log(base4)(x+1) + 2log(base4)(x-1)] +6log(base4)(x)
\n" ); document.write( "this looks to me like:
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\n" ); document.write( "you have a couple of concepts to work with:
\n" ); document.write( "these are:
\n" ); document.write( "\"log%284%2Ca%29+%2B+log%284%2Cb%29+=+log%284%2Ca%2Ab%29\"
\n" ); document.write( "\"c%2Alog%284%2Ca%29+=+log%284%2Ca%5Ec%29\"
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\n" ); document.write( "we will remove the inner parentheses first and work outwards.
\n" ); document.write( "you have:
\n" ); document.write( "\"2%2Alog%284%2Cx-1%29\"
\n" ); document.write( "this becomes:
\n" ); document.write( "\"log%284%2C%28x-1%29%5E2%29\"
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\n" ); document.write( "working our way outwards, you have:
\n" ); document.write( "\"log%284%2Cx%2B1%29+%2B+log%284%2C%28x-1%29%5E2%29\"
\n" ); document.write( "this becomes:
\n" ); document.write( "\"log%284%2C%28x%2B1%29%2A%28x-1%29%5E2%29\"
\n" ); document.write( "working our way outwards again, you have:
\n" ); document.write( "\"%281%2F2%29%2A%28log%284%2C%28x%2B1%29%2A%28x-1%29%5E2%29%29\"
\n" ); document.write( "this becomes:
\n" ); document.write( "\"log%284%2C%28%28x%2B1%29%2A%28x-1%29%5E2%29%5E%281%2F2%29%29\"
\n" ); document.write( "we now have in total:
\n" ); document.write( "\"log%284%2C%28%28x%2B1%29%2A%28x-1%29%5E2%29%5E%281%2F2%29%29+%2B+6%2Alog%284%2Cx%29\"
\n" ); document.write( "\"6%2Alog%284%2Cx%29+=+log%284%2Cx%5E2%29\"
\n" ); document.write( "so we have:
\n" ); document.write( "\"log%284%2C%28%28x%2B1%29%2A%28x-1%29%5E2%29%5E%281%2F2%29%29+%2B+log%284%2Cx%5E6%29\"
\n" ); document.write( "and this becomes:
\n" ); document.write( "\"log%284%2C%28%28%28x%2B1%29%2A%28x-1%29%5E2%29%5E%281%2F2%29%2Ax%5E6%29%29\"
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\n" ); document.write( "i checked the answer and it appears to be good.
\n" ); document.write( "i did this by solving both equations for a given value of x.
\n" ); document.write( "i used x = 2.
\n" ); document.write( "i got the same answer both ways (the original equation and the condensed equation).
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\n" ); document.write( "you can solve this as well if you wish to prove the answer is good.
\n" ); document.write( "you can use your calculator by converting to base 10 as follows:
\n" ); document.write( "\"log4%2Cx%29+=+log%2810%2Cx%29%2Flog%2810%2C4%29\"
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