document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24227>Question 24227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 loga X + loga 2 = loga (5x+3)\r<BR>\n" );
document.write( "\n" );
document.write( "I thought:\r<BR>\n" );
document.write( "\n" );
document.write( " X^2 + 2 = 5X+3<BR>\n" );
document.write( " X^2 -5X - 1 = 0\r<BR>\n" );
document.write( "\n" );
document.write( "The answer is suppose to be 3. I don't understand how to get there since it doesn't factor. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12892 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE MY COMMENTS BELOW<BR>\n" );
document.write( "2 loga X + loga 2 = loga (5x+3)..ALL ARE TO SAME BASE A . SO WE CAN DROP THE BASE.\r<BR>\n" );
document.write( "\n" );
document.write( "I thought:\r<BR>\n" );
document.write( "\n" );
document.write( " X^2 + 2 = 5X+3..YOU DID 2*LOG X = LOG (X^2)..GOOD..BUT BEFORE TAKING ANTILOGS ,YOU SHOULD BRING L.H.S. AND R.H.S. TO SINGLE LOG TERM.R.H.S. HAS ONLY ONE LOG TERM LOG (5X+3)..IT IS OK .BUT L.H.S .HAS 2 LOG TERMS .............<BR>\n" );
document.write( "LOG (X^2)+LOG 2..FIRST YOU SHOULD COMBINE THEM INTO ONE ..USING....<BR>\n" );
document.write( "LOG X +LOG Y = LOG (X*Y).SO WE GET L.H.S. AS<BR>\n" );
document.write( " LOG (X^2)+LOG 2 = LOG (2*X^2),SO THAT WE HAVE LOG (2*X^2)=LOG (5X+3)..NOW WE CAN TAKE ANTILOGS.TO GET 2*X^2=5X+3<BR>\n" );
document.write( "2X^2-5X-3=0<BR>\n" );
document.write( "2X^2-6X+X-3=0..(I THINK YOU KNOW THIS .OTHERWISE COME BACK & I SHALL EXPLAIN)<BR>\n" );
document.write( "2X(X-3)+1(X-3)=0<BR>\n" );
document.write( "(X-3)(2X+1)=0<BR>\n" );
document.write( "HENCE X-3 = 0 ...OR...X=3<BR>\n" );
document.write( "THE OTHER ALTERNATIVE 2X+1=0..GIVES...2X=-1...OR X=-1/2..WHICH LEADS TO LOG OF A NEGATIVE NUMBER AND HENCE IS NOT PERMISSIBLE.<BR>\n" );
document.write( "HENCE X=3\r<BR>\n" );
document.write( "\n" );
document.write( " answer is suppose to be 3. I don't understand how to get there since it doesn't factor. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );