document.write( "Question 24246: The sum of the squares of two consecutive positive even integers is 340. What are the integers? The answer should be in this form: 6 and 7 \n" ); document.write( "
Algebra.Com's Answer #12891 by Earlsdon(6294)\"\" \"About 
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Let the first positive even integer = x, then the next consecutive positive even integer = (x+2)\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+%28x%2B2%29%5E2+=+340\" Simplify the left side.
\n" ); document.write( "\"x%5E2+%2B+%28x%5E2+%2B+4x+%2B+4%29+=+340\"
\n" ); document.write( "\"2x%5E2+%2B+4x+%2B+4+=+340\" Subtract 340 from both sides of the equation.
\n" ); document.write( "\"2x%5E2+%2B+4x+-+336+=+0\" Factor a 2 from the left side.
\n" ); document.write( "\"2%28x%5E2+%2B+2x+-+168%29+=+0\" Factor the parentheses.
\n" ); document.write( "\"2%28x-12%29%28x%2B14%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"%28x-12%29+=+0\" and/or \"%28x%2B14%29+=+0\"
\n" ); document.write( "If \"x-12+=+0\" then \"x+=+12\" This is the first postive even integer.
\n" ); document.write( "If \"x%2B14+=+0\" then \"x+=+-14\" Discard this solution as you want positive integers only.\r
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\n" ); document.write( "\n" ); document.write( "The two integers are: 12 and 14\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"12%5E2+%2B+14%5E2+=+144+%2B+196\" = 340
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