document.write( "Question 173986: Okay, this is just part of an equation involving fractions that i am doing, but i was wondering,can you factor u^2+u^2v^2+v^2 into two binomials? Thats all i really need for the problem. \r
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Algebra.Com's Answer #128897 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Looking at \"u%5E2%2Bu%5E2v%5E2%2Bv%5E2\" we can see that the first term is \"u%5E2\" and the last term is \"v%5E2\" where the coefficients are 1 and 1 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient 1 to get 1. Now what two numbers multiply to 1 and add to the middle coefficient 1? Let's list all of the factors of 1:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 1:\r
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\n" ); document.write( "\n" ); document.write( "-1 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 1\r
\n" ); document.write( "\n" ); document.write( "1*1\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-1)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 1\r
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First NumberSecond NumberSum
111+1=2
-1-1-1+(-1)=-2
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\n" ); document.write( "\n" ); document.write( "None of these pairs of factors add to 1. So the expression \"u%5E2%2Bu%5E2v%5E2%2Bv%5E2\" cannot be factored\r
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