document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173982>Question 173982</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780073533520/algebrahomeworkh>algebra for college students</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Line l is perpendicular to a line with slope -5. Both lines contain the origin </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128882 by </B><A HREF=/tutors/aboutme.mpl?userid=bob123132><B>bob123132(33)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bob123132><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well if you are looking for the slope of the second line then it is always the  negative reciprocal of the other slope so in this case the slope in this perpendicular line is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F5 ALIGN=MIDDLE  ALT=\"1%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >. If you are looking to put another point on the graph remember that the formula is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=RISE%2FRUN ALIGN=MIDDLE  ALT=\"RISE%2FRUN\"   DISABLED_style= \"max-width:90%; height:auto;\" > So the slope is a rise of 1 and a run of 5 so count 1 up from a point and right five OR count down 1 point and left 5.\r<BR>\n" );
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document.write( "Ex co-ordinates of point A are (5,2) and B is (6,-3) where is point C if it is perpendicular to lineAB. It can be C(11,-2) or C(1,-4) </SPAN>\n" );
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