document.write( "Question 173792: Given that the roots of x^2+px+q=0 are (alpha) and 4(alpha) show that 4p^2= 25q. \n" ); document.write( "
Algebra.Com's Answer #128853 by solver91311(24713)\"\" \"About 
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The roots of \"x%5E2%2Bpx%2Bq=0\" are \"alpha\" and \"4alpha\" if and only if \"%28x-alpha%29\" and \"%28x-4alpha%29\" are factors of \"x%5E2%2Bpx%2Bq\". So:\r
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\n" ); document.write( "\n" ); document.write( "Hence: \"p=-5alpha\" and \"q=4alpha%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"4p%5E2=4%28-5alpha%29%5E2=4%2A25alpha%5E2=100alpha%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"25q=25%2A4alpha%5E2=100alpha%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "QED
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