document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173957>Question 173957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have got all my problems worked out except this one. I have a problem when it comes to the elimination method. PLEASE EXPLAIN! 0.05x+0.25y=66  0.15x+0.05y=72 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128848 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128848\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PLEASE EXPLAIN! <BR>\n" );
document.write( "0.05x+0.25y=66 <BR>\n" );
document.write( "0.15x+0.05y=72<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "To use elimination (and then substitution) multiply one or both eqns to get the same coeffs for one of the variables.<BR>\n" );
document.write( "In these 2, multiplying the 1st eqn by 3 will give the same coeffs for x<BR>\n" );
document.write( "0.05x+0.25y=66 <BR>\n" );
document.write( "0.15x+0.75y=198  eqn1 times 3<BR>\n" );
document.write( "0.15x+0.05y=72  Then subtract 2 from 1<BR>\n" );
document.write( "0.0x+ 0.70y=126<BR>\n" );
document.write( "7y = 1260<BR>\n" );
document.write( "y = 180<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Sub for y into either eqn<BR>\n" );
document.write( "0.05x + 0.25*180 = 66<BR>\n" );
document.write( "5x + 4500 = 6600<BR>\n" );
document.write( "5x = 2100<BR>\n" );
document.write( "x = 420\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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