document.write( "Question 173903: Ok so I've tried to do this problem quite a few times and I just can't seem to get it.
\n" ); document.write( "2x+5y=19
\n" ); document.write( "x=32-7y
\n" ); document.write( "I tried to solve by substitution, I did this:
\n" ); document.write( "2(32-7y)+5y=19
\n" ); document.write( "64-14y+5y=19
\n" ); document.write( "20y=83
\n" ); document.write( "But as you can see that is not right, I cannot figure out what I am doing wrong. I am supposed to end up with an ordered pair, I just don't get it.
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Algebra.Com's Answer #128788 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Your system:\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B5y=19\"
\n" ); document.write( "\"x=32-7y\"\r
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\n" ); document.write( "\n" ); document.write( "Your solution:\r
\n" ); document.write( "\n" ); document.write( "\"2%2832-7y%29%2B5y=19\" Ok, spot on.
\n" ); document.write( "\"64-14y%2B5y=19\" Still going well.
\n" ); document.write( "\"20y=83\" Oops! How did you manage to add \"-14y\" to \"5y\" and come up with \"20y\"? \"-14y%2B5y=-9y\". Also, you subtracted 64 from the left side, but added it to the right side. You need to subtract 64 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"64-14y%2B5y=19\"\r
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\n" ); document.write( "\n" ); document.write( "\"-9y=19-64\"\r
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\n" ); document.write( "\n" ); document.write( "\"-9y=-45\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=5\"\r
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\n" ); document.write( "\n" ); document.write( "Half done. Now you need to go back and use this value for \"y\" to calculate the value for \"x\" that satisfies both equations.\r
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\n" ); document.write( "\n" ); document.write( "So take \"x=32-7y\" and substitute \"5\" for \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=32-7%285%29=32-35=-3\"\r
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\n" ); document.write( "\n" ); document.write( "Now you can write your ordered pair because you have an \"x\" value and a corresponding \"y\" value.\r
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\n" ); document.write( "\n" ); document.write( "The solution set for your system is (\"-3\",\"5\").\r
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\n" ); document.write( "\n" ); document.write( "Ah, ah, ah...not so fast. We still need to check the answers. Substituting the values of x and y into both equations must result in two true statements. Let's see:\r
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\n" ); document.write( "\n" ); document.write( "\"2%28-3%29%2B5%285%29=-6%2B25=19\" True\r
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\n" ); document.write( "\n" ); document.write( "\"-3=32-7%285%29=-3\" True\r
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\n" ); document.write( "\n" ); document.write( "Answer checks.
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