document.write( "Question 173895: A rectangle has a perimeter of 140 Square feet. Maximize the area of the rectangle \n" ); document.write( "
Algebra.Com's Answer #128777 by solver91311(24713) You can put this solution on YOUR website! Perimeter: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solving for L: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since A(W) is continuous and differentiable the first derivitive set to zero gives the value of the independent variable at a local extrema.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the first derivitive is also differentiable, the sign on the second derivitive at the extreme point will characterize the extreme as a maximum or minimum.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, a rectangle with perimeter 140 has a maximum area when the width is 35, which means that the length is also 35 and the rectangle is actually a square. \n" ); document.write( " |