document.write( "Question 173877: log5X+log15=0\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #128767 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Applying \"log rules\":
\n" ); document.write( "log5x+log15=0
\n" ); document.write( "log75x=0
\n" ); document.write( "75x = 10^0
\n" ); document.write( "75x = 1
\n" ); document.write( "x = 1/75\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );