document.write( "Question 173684: Given that f(x) = x2 + 3 and D = {reals}, find f(-3).
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document.write( "Given that g(x) = x + 4 and D = {reals}, find g(3).
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document.write( "Given that f(x) = 3x + 1 and D = {integers}, find f(-2).
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document.write( "Given that h(x) = x2 - 3 and D = {reals, find h(-4).
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document.write( "Given that g(x) = 2x - 1 and D = {integers}, find g(5).
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document.write( "Given that f(x) = 3x + 1 and D = {reals}, find f(-6).
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document.write( "Given that f(x) = x2 -2x and D = {reals}, find f(2).
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document.write( "Given that f(x) = x - 3 and D = {reals}, find f(-2).
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document.write( "Given that f(x) = 2x2 and D = {reals}, find f(4).
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document.write( "Given that f(x) = 2x3 and D = (reals}, find f(2). \n" );
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Algebra.Com's Answer #128755 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! Given f(x) = some function of x, to evaluate f(a), just substitute a for x whereever it occurs in the function and do the arithmetic. I presume D stands for domain, so since all of your values are integers, you don't have any excluded values in any of the stated domains.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's how to do the first one:\r \n" ); document.write( "\n" ); document.write( "Given that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do the rest of them the same way. \n" ); document.write( " |