document.write( "Question 24191: Mark's football is stuck in a tree. He hopes to dislodge it by standing on a small hill and throwing a baseball at it. Use the fact that a dropped object falls a distance of 4.9t2 meters in t seconds. Mark throws the baseball with an initial vertical velocity of 14.7 m/s from a height of 3m.\r
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document.write( "A. What maximum height does the baseball reach?
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document.write( "B. If the football is 12m above the ground, at what time(s) could the baseball hit it? \n" );
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Algebra.Com's Answer #12875 by josmiceli(19441) You can put this solution on YOUR website! When Mark throws the baseball up, only the vertical part of the velocity he \n" ); document.write( "gives it counts, because the horizontal part just moves the ball sideways \n" ); document.write( "14.7t is his vertical throwing velocity times the time at any point in the baseball's trajectory. \n" ); document.write( "4.9t^2 is the downward velocity due to falling (gravity) \n" ); document.write( "this is the equation: \n" ); document.write( " \n" ); document.write( "this is the equation for vertical height in meters. Note that when h = 3, \n" ); document.write( "the height is zero, as it should be. \n" ); document.write( "plugging in 1 sec for t, I get the same answer for h that I get \n" ); document.write( "when I plug in 2 sec. \n" ); document.write( "That means that the baseball is the same height on the way up at 1 sec as it \n" ); document.write( "is on the way down in 2 sec. \n" ); document.write( "That means it reaches the max height in the middle, or 1.5 sec. \n" ); document.write( "plug 1.5 into the equation and that will give you the max height. \n" ); document.write( " \n" ); document.write( " |