document.write( "Question 24191: Mark's football is stuck in a tree. He hopes to dislodge it by standing on a small hill and throwing a baseball at it. Use the fact that a dropped object falls a distance of 4.9t2 meters in t seconds. Mark throws the baseball with an initial vertical velocity of 14.7 m/s from a height of 3m.\r
\n" ); document.write( "\n" ); document.write( "A. What maximum height does the baseball reach?
\n" ); document.write( "B. If the football is 12m above the ground, at what time(s) could the baseball hit it?
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Algebra.Com's Answer #12875 by josmiceli(19441)\"\" \"About 
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When Mark throws the baseball up, only the vertical part of the velocity he
\n" ); document.write( "gives it counts, because the horizontal part just moves the ball sideways
\n" ); document.write( "14.7t is his vertical throwing velocity times the time at any point in the baseball's trajectory.
\n" ); document.write( "4.9t^2 is the downward velocity due to falling (gravity)
\n" ); document.write( "this is the equation:
\n" ); document.write( "\"14.7+%2A+t+-+4.9+%2A+t%5E2+=+h+-+3\"
\n" ); document.write( "this is the equation for vertical height in meters. Note that when h = 3,
\n" ); document.write( "the height is zero, as it should be.
\n" ); document.write( "plugging in 1 sec for t, I get the same answer for h that I get
\n" ); document.write( "when I plug in 2 sec.
\n" ); document.write( "That means that the baseball is the same height on the way up at 1 sec as it
\n" ); document.write( "is on the way down in 2 sec.
\n" ); document.write( "That means it reaches the max height in the middle, or 1.5 sec.
\n" ); document.write( "plug 1.5 into the equation and that will give you the max height.
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