document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173829>Question 173829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Graph the line with slope -2/3 passong through the point (-5,5). I cannot do this problem. I have tried  and when it comes to math I can't add 3 + 3. The negatives are the worst along with fractions. I just don't understand it.Can anybody figure this out and show me how? Ty in advance. Judy  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128702 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The general equation for a line is y=mx+c\r<BR>\n" );
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document.write( "m= slope\r<BR>\n" );
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document.write( "Replace m with -2/3  y=-2/3x +c\r<BR>\n" );
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document.write( "Plug in the value for the point\r<BR>\n" );
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document.write( "5=-2/3(-5) +c\r<BR>\n" );
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document.write( "We are trying to find the y intercept c\r<BR>\n" );
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document.write( "5=10/3+c\r<BR>\n" );
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document.write( "Subract 10/3 to both sides\r<BR>\n" );
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document.write( "15/3 -10/3= c\r<BR>\n" );
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document.write( "5/3= c\r<BR>\n" );
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document.write( "Let's double check that this is the correct linear equation\r<BR>\n" );
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document.write( "5=10/3 +5/3\r<BR>\n" );
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document.write( "Therefore the eqation is y=-2/3x+5/3<BR>\n" );
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document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=describe_linear_equation.solver>DESCRIBE a linear EQUATION: slope, intercepts, etc</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>Equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2+x+%2B+3+y+=+5 ALIGN=MIDDLE  ALT=\"2+x+%2B+3+y+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" > describes a sloping line. For any <BR>\n" );
document.write( "  equation ax+by+c = 0, slope is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-a%2Fb+=+-2%2F3 ALIGN=MIDDLE  ALT=\"-a%2Fb+=+-2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<UL><LI>X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x =  c/a. 5/2 = 2.5.</LI><LI>Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 5/3 = 1.66666666666667.</LI><LI>Slope is -2/3 = -0.666666666666667.</LI><LI> Equation in slope-intercept form: y=-0.666666666666667*x+1.66666666666667.</LI></UL><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28+500%2C+500%2C+2.5-8%2C+2.5%2B8%2C+1.66666666666667-8%2C+1.66666666666667%2B8%2C+-0.666666666666667%2Ax%2B1.66666666666667+%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\n" );
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