document.write( "Question 173829: Graph the line with slope -2/3 passong through the point (-5,5). I cannot do this problem. I have tried and when it comes to math I can't add 3 + 3. The negatives are the worst along with fractions. I just don't understand it.Can anybody figure this out and show me how? Ty in advance. Judy \n" ); document.write( "
Algebra.Com's Answer #128700 by jojo14344(1513)\"\" \"About 
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Graph the line with slope -2/3 passong through the point (-5,5).
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\n" ); document.write( "Okay, good you have the \"slope=m=-2%2F3\"
\n" ); document.write( "Thru point (-5,5), via Slope-Intercept form, \"y=mx%2Bb\", solving for y-inyercept \"b\":
\n" ); document.write( "\"5=%28-2%2F3%29%28-5%29%2Bb\"
\n" ); document.write( "\"5=10%2F3%2Bb\"---->\"b=5-%2810%2F3%29=%2815-10%29%2F3=5%2F3\", Y-intercept
\n" ); document.write( "Then, it follows our eqn-----> \"y=%28-2%2F3%29x%2B%285%2F3%29\"
\n" ); document.write( "As we see in the graph:
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\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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