document.write( "Question 173777: what is the answer using the elimination/addition method to:\r
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document.write( "2w+3z=17
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document.write( "3w+4z=24 \n" );
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Algebra.Com's Answer #128645 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! answer using the elimination/addition method to: \n" ); document.write( "2w+3z=17 \n" ); document.write( "3w+4z=24 \n" ); document.write( "---------- \n" ); document.write( "Multiply 1t by 3 and 2nd by 2 to get: \n" ); document.write( "6w + 9z = 51 \n" ); document.write( "6w + 8z = 48 \n" ); document.write( "--------------- \n" ); document.write( "Subtract 2nd from 1st and solve for \"z\": \n" ); document.write( "z = 3 \n" ); document.write( "--------- \n" ); document.write( "Substitute into 2w + 3z = 17 and solve for \"w\" \n" ); document.write( "2w + 3*3 = 17 \n" ); document.write( "2w = 8 \n" ); document.write( "w = 4 \n" ); document.write( "--------- \n" ); document.write( "Ans: w = 4; z = 3 \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "stan H. \n" ); document.write( " \n" ); document.write( " |