document.write( "Question 173777: what is the answer using the elimination/addition method to:\r
\n" ); document.write( "\n" ); document.write( "2w+3z=17
\n" ); document.write( "3w+4z=24
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Algebra.Com's Answer #128645 by stanbon(75887)\"\" \"About 
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answer using the elimination/addition method to:
\n" ); document.write( "2w+3z=17
\n" ); document.write( "3w+4z=24
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\n" ); document.write( "Multiply 1t by 3 and 2nd by 2 to get:
\n" ); document.write( "6w + 9z = 51
\n" ); document.write( "6w + 8z = 48
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\n" ); document.write( "Subtract 2nd from 1st and solve for \"z\":
\n" ); document.write( "z = 3
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\n" ); document.write( "Substitute into 2w + 3z = 17 and solve for \"w\"
\n" ); document.write( "2w + 3*3 = 17
\n" ); document.write( "2w = 8
\n" ); document.write( "w = 4
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\n" ); document.write( "Ans: w = 4; z = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.
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