document.write( "Question 173741: Hello,
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document.write( "My question concerns growth, but I do not understand how to use the log in the equation. It reads f(x)=400 log10 (2t+3). It is asking how many animals will there be after six months. Can you help me make sense of this problem? Thank you ever so much. \n" );
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Algebra.Com's Answer #128617 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! My question concerns growth, but I do not understand how to use the log in the equation. It reads f(x)=400 log10 (2t+3). It is asking how many animals will there be after six months. \n" ); document.write( ": \n" ); document.write( "Assume you mean log,base10, which can just be written log( ), so we have \n" ); document.write( "f(t) = 400*log(2t+3) \n" ); document.write( ": \n" ); document.write( "Find f(t) when t = 6 \n" ); document.write( "f(t) = 400 * log[2(6) + 3] \n" ); document.write( "; \n" ); document.write( "f(t) = 400 * log(12 + 3) \n" ); document.write( ": \n" ); document.write( "f(t) = 400 * log(15) \n" ); document.write( ": \n" ); document.write( "Find the log of 15 \n" ); document.write( "f(t) = 400 * 1.1761 \n" ); document.write( ": \n" ); document.write( "f(t) = 470 animals after 6 months \n" ); document.write( ": \n" ); document.write( "Hope this is what you mean. \n" ); document.write( " |