document.write( "Question 173478: 1/(2X-4)- 2/(y+1)=0 and 1/(x-3)- 1/(y+4)=0
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document.write( "Solve using elimination: \n" );
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Algebra.Com's Answer #128614 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1/(2X-4)- 2/(y+1)=0 and 1/(x-3)- 1/(y+4)=0 \n" ); document.write( "Solve using elimination: \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation by (2x-4)(y+1) to get rid of the denominators, results \n" ); document.write( "(y+1) - 2(2x-4) = 0 \n" ); document.write( "y + 1 - 4x + 8 = 0 \n" ); document.write( "-4x + y + 9 = 0 \n" ); document.write( "-4x + y = -9 \n" ); document.write( "4x - y = 9; multiplied by -1 \n" ); document.write( " and \n" ); document.write( " \n" ); document.write( "Multiply by (x-3)(y+4), results: \n" ); document.write( "(y + 4) - (x - 3) = 0 \n" ); document.write( "y + 4 - x + 3 = 0 \n" ); document.write( "-x + y + 7 = 0 \n" ); document.write( "-x + y = -7 \n" ); document.write( ": \n" ); document.write( "Add the two equations \n" ); document.write( "4x - y = 9 \n" ); document.write( "-x + y = -7; \n" ); document.write( "---------------adding eliminates y, find x \n" ); document.write( "3x = 2 \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "Use the last equation to find y: \n" ); document.write( "- \n" ); document.write( "y = -7 + \n" ); document.write( "y = -6 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in the 2nd original equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "I'll let you check it in the 1st original equation \n" ); document.write( " |