document.write( "Question 173709: Solve by addition or substitution.\r
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document.write( "3x + 5y = 2
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document.write( "2x + 5y = -2 \n" );
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Algebra.Com's Answer #128606 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! We will solve this by addition; \n" ); document.write( "3x + 5y = 2 \n" ); document.write( "(-1)2x + 5y = -2 \n" ); document.write( "==================== \n" ); document.write( "3x +5y = 2 \n" ); document.write( "-2x -5y = 2 \n" ); document.write( "------------ \n" ); document.write( "x=4 \n" ); document.write( "Now that we have our x lets plug that in to find y; \n" ); document.write( "3(4)+5y=2 \n" ); document.write( "12 +5y =2 \n" ); document.write( "5y = -10 \n" ); document.write( "y = -2 \n" ); document.write( "============= \n" ); document.write( ":) \n" ); document.write( " \n" ); document.write( " |